How to check the output in console after escaping?

Question

Assume there are two strings:

str1 = 'a\ba'
str2 = 'a'

If we use print to show those strings, all of them will print a.

But obviously, str1 == str2 is False.How could I check whether they are the same after escaping?

Expected output like: f(str1) == str2 is True,f() is the function to get the string after escaping.

I am not looking forward for some arithmetic ways to achieve that.

Do you want to check whether strings are different after printing? Or at what stage? — NotAName, Oct 19 '20 at 02:49
@pavel Yes, just want to know whether strings are different after printing. — Kevin Mayo, Oct 19 '20 at 02:52
Does this answer your question? [Process escape sequences in a string in Python](https://stackoverflow.com/questions/4020539/process-escape-sequences-in-a-string-in-python) — jkr, Oct 19 '20 at 03:23
This is terminal-dependant; see the comments on https://stackoverflow.com/questions/53322564/python-process-escape-characters. — Brian McCutchon, Oct 19 '20 at 03:44

Zhubei Federer · Accepted Answer · 2020-10-19T03:39:26.483

1

\b in ASCII is backspace (BS),it will not show in print function,

1. If you want it show in print function,you can use:

>>> print(repr(str1))
'a\x08a'

2. If you want use this str1 as print,you need to remove backspace :

>>> re.sub('.\b', '', str1)
'a'

edited Oct 19 '20 at 03:39

answered Oct 19 '20 at 02:54

Zhubei Federer

You maybe misunderstand me. – Kevin Mayo Oct 19 '20 at 03:00
Thanks, that's close to what I want. – Kevin Mayo Oct 19 '20 at 03:51
1

The second approach fails for strings like `ab\b\bc`. It should give `c`, but it instead gives `a\bc`. CC @KevinMayo – Brian McCutchon Oct 19 '20 at 04:32
@BrianMcCutchon yes~it just an example, and it can do re.sub() again of ```a\bc``` to get ```c``` – Zhubei Federer Oct 19 '20 at 05:09
@BrianMcCutchon Yes, thanks for explaining, so finally, I had to use some arithmetic ways to achieve that. – Kevin Mayo Oct 19 '20 at 08:08
This answer might also help https://stackoverflow.com/a/24519338/5666087 – jkr Oct 19 '20 at 18:37

1 Answers1