How to add an optional slug in a Django Url

Question

I want to add an optional Stackoverlow like slug to my urls in Django

path(
    r"item/<int:pk>/<slug:slug>",
    ItemDetailView.as_view(),
    name="item_detail",
),

How do I make the slug optional so that it works in all three cases:

item/1
item/1/
item/1/slug

As far as I know there is no option to treat parameters in url as optional. In this case you need to create two paths linked with one view — ImustAdmit, Oct 21 '20 at 14:43
Does this answer your question? [Django optional url parameters](https://stackoverflow.com/questions/14351048/django-optional-url-parameters) — iklinac, Oct 21 '20 at 14:55

score 2 · Answer 1 · edited Oct 22 '20 at 00:44

2

You can achieve this using re_path

from django.urls import re_path

urlpatterns = [
    re_path(r'^item/(?P<pk>[0-9]+)(?:/(?P<slug>[-\w]+))?/$', ItemDetailView.as_view(), name="item_detail"),
]

edited Oct 22 '20 at 00:44

Dharman

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answered Oct 21 '20 at 15:43

Mahmudul Alam

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score 0 · Answer 2 · answered Oct 21 '20 at 14:42

0

The easiest way to do it is using different paths:

urlpatterns = [
    path('item/<int:pk>/', ItemDetailView.as_view(), name="item_detail"),
    path('item/<int:pk>/<slug:slug>/', ItemDetailView.as_view(), name="item_detail"),
]

answered Oct 21 '20 at 14:42

Shinra tensei

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How to add an optional slug in a Django Url

2 Answers2