Python Comparison using While Loop

Question

I am learning the basics of programming using Python and I am trying to compare a variable to another. Here's what I have:

code = "03"
count = 0

npw=str(input("Enter code: "))
while count != 2:
    if npw == code:
        print("Success")
        break
    else:
        print("incorrect")
        npw=str(input("Enter code: "))
        count += 1
print("Reached Maximum Tries")

I want the user to have 3 tries to guess the code, but upon trying 3 tries, the third one was not read. Also, when I entered the correct code, it also prints the "Reached Maximum Tries". Thanks in Advance.

You print "Reached Maximum Tries" because it is outside the loop. It will always be printed no matter what happens inside the loop. — Ale, Oct 27 '20 at 22:53
`str()` is unnecssary on `input()`. `input()` returns a `str` already. — Mark Tolonen, Oct 27 '20 at 23:06
Thank you for all the help guys! I really appreciate the help. Now I am learning in the right direction. — veryap19, Oct 27 '20 at 23:09

score 0 · Answer 1 · answered Oct 27 '20 at 22:51

0

You check if the code is correct before asking for the last time! Change the order around to fix that problem.
You always print "Max". You can do that using else. See this question for examples.
Minor point: you don't need to convert strings to strings!

Final solution:

code = "03"

for count in range(3):
    npw = input("Enter code")
    if npw == code:
        print("Success")
        break
    print("Incorrect")
else:
    print("Max")

answered Oct 27 '20 at 22:51

Jasmijn

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Thank you for your help Ma'am! I am still learning the ropes and I find that this is challenging with my age (40) and my learning curve is not the same when I was young. :) I have been thinking too hard not knowing that using "For" instead of "While" will do the trick. Thanks again – veryap19 Oct 27 '20 at 23:01

Python Comparison using While Loop

1 Answers1