REGEX - Remove decimals from string

Question

I'm looking for some REGEX or some other way in JS how to remove decimal numbers from string.

example input:

Mazda 6 2.0 Skyactiv-G Wagon 2018 - Startstop.sk - TEST
Mercedes C63 AMG Sound REVVING 6,3l V8

example output:

Mazda 6 Skyactiv-G Wagon 2018 - Startstop.sk - TEST
Mercedes C63 AMG Sound REVVING l V8

Everywhere I look people want to keep both integers and decimals and just remove strings. But I want to keep all integers just remove decimals (with comma, or dot.)

I tried something like:

var string = "Mazda 6 2.0 Skyactiv-G Wagon 2018 - Startstop.sk - TEST"
parseFloat(string.match(/[\d\.]+/))
// Result is 6

But this actually just again remove everything exept integers.

Match 1 or more digits followed by a decimal part starting either with a dot or comma `\d+(?:[.,]\d)+` — The fourth bird, Oct 29 '20 at 16:12
`6,3l`? This is a lowercase "L" character. Is that intentional or should it be a 1 (digit one)? `re.sub(r"\b\d+[.,]\d+\b ?", "", s)`? — ggorlen, Oct 29 '20 at 16:14
@Thefourthbird it seems your answer is yet the only one so feel free to write it as asnwer not a comment and I will accept it — Andurit, Oct 29 '20 at 16:18
There are possible duplicate questions like for example https://stackoverflow.com/questions/7886593/regex-validation-of-decimal-numbers-with-comma-or-dot — The fourth bird, Oct 29 '20 at 16:25
@Thefourthbird The main issue with them is that most of them match both ints and floats. Matching `\d+\.\d+` is so evident that no one asks for such patterns. — Wiktor Stribiżew, Oct 29 '20 at 16:42
I would post an answer, just add `\s*` at the start, and suggest `.trim()`ing. — Wiktor Stribiżew, Oct 29 '20 at 16:46

Mamun · Answer 1 · 2020-10-29T16:41:02.630

2

You can try \s\d*\.\d+\s

Where

\s - matches any whitespace character

\d* - matches digit (equal to [0-9]) between zero and unlimited times

\. - matches the character . literally

d+ - matches digit (equal to [0-9]) between one and unlimited times

var string = `Mazda 6 2.0 Skyactiv-G Wagon 2018 - Startstop.sk - TEST
Mercedes C63 AMG Sound REVVING 6,3l V8`
console.log(string.replace(/\s\d*\.\d+\s|\s\d*,\d+/gm, ' '));

edited Oct 29 '20 at 16:41

answered Oct 29 '20 at 16:15

Mamun

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result should be `Mazda 6 Skyactiv-G Wagon 2018 - Startstop.sk - TEST` not `2` – Andurit Oct 29 '20 at 16:18
@Andurit, you are right, updated the answer, thanks:) – Mamun Oct 29 '20 at 16:22
Thanks @Mamun but this works only with `.` not with `,`. As my second example `Mercedes C63 AMG Sound REVVING 6,3l V8 ` – Andurit Oct 29 '20 at 16:26
@Andurit, I have updated the answer, please check:) – Mamun Oct 29 '20 at 16:42
Thanks, I'm giving you thumbs up for right answer however I decided to accept other answer as it was first :) – Andurit Oct 29 '20 at 17:49

The fourth bird · Accepted Answer · 2020-10-29T19:21:42.940

You can match bot a dot and a comma using a character class [,.] and match 1 or more digits before and after it.

Instead of using string.match you can use string.replace and using an empty string in the replacement.

Matching optional leading whitespace chars to prevent the double space gaps after removing only the digits:

\s*\d+[.,]\d+

Regex demo

var string = "Mazda 6 2.0 Skyactiv-G Wagon 2018 - Startstop.sk - TEST"
string = string.replace(/\s*\d+[.,]\d+/g, "");
console.log(string);

Or matching 1 or more times a dot or comma followed by 1 or more digits, you can use a repeated non capturing group:

\s*\d+(?:[.,]\d+)+

aziz k'h · Answer 3 · 2020-10-29T16:27:50.850

0

var string = "Mazda 6 2.0 Skyactiv-G Wagon 2018 - Startstop.sk - TEST";
regex = /\d+(\.\d+)/g;
string = string.replace(regex, "");
console.log(string);

result :

Mazda 6  Skyactiv-G Wagon 2018 - Startstop.sk - TEST

explain :

\d :  Matches any digit character (0-9).
+ :   Match 1 or more of the preceding token.
[\.,] : Match "." character  or "," character.

edited Oct 29 '20 at 16:27

answered Oct 29 '20 at 16:19

aziz k'h

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REGEX - Remove decimals from string

3 Answers3