How to extract the element from the dictionary without last item

Question

I need to re-instantiate the dictionary without last element

Below are sample list and dictionary

List of Dictionary

[{'emptype': ['Manager'],
  'Designation': ['Developer'],
  'projecttype': ['temp']}]

Dictionary

{'emptype': ['Manager'],
  'Designation': ['Developer'],
  'projecttype': ['temp']}

How to extract the elements except last

Expected out from list of dictionary

[{'emptype': ['Manager'],
  'Designation': ['Developer']}]

Expected out from dictionary

 {'emptype': ['Manager'],
      'Designation': ['Developer']}

Suggest you to do it only in ordered dictionary... python built-in dict is not necessarily ordered so u cant expect any of the key-value pairs to stay consistently last or first — adir abargil, Nov 28 '20 at 15:38
But i m using python 3.8 so its feauture now, no need of orderdict — , Nov 28 '20 at 15:45

arabinelli · Accepted Answer · 2020-11-28T16:03:34.767

1

Using map:

d = [{'emptype': ['Manager1'],
  'Designation': ['Developer1'],
  'projecttype': ['temp1']},
   {'emptype': ['Manager2'],
  'Designation': ['Developer2'],
  'projecttype': ['temp2']},
  {'emptype': ['Manager3'],
  'Designation': ['Developer3'],
  'projecttype': ['temp3']},
  {'emptype': ['Manager4'],
  'Designation': ['Developer4'],
  'projecttype': ['temp4']}]

def remove_last_key(item: dict):
    item.pop(
        list(item.keys())[-1]
    )
    return item

list(map(remove_last_key,d))

This was tested on Python 3.7.7 (and should work on 3.6+) - When working on dict based on their order, the Python version matters. You can read more here: Are dictionaries ordered in Python 3.6+?

EDIT:

In certain cases, list comprehension might provide some advantages in terms of performance and are considered clearer by some. In this case:

[remove_last_key(item) for item in d]

edited Nov 28 '20 at 16:03

answered Nov 28 '20 at 15:55

arabinelli

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Is it compulsory to write the function, can we write without function, your code is working fine – Nov 28 '20 at 16:02
1

@Maws You can still use the one liner i showed you... – adir abargil Nov 28 '20 at 16:04
I personally find that using a function improves readability, but it's not mandatory, as @adirabargil's answer demonstrates. – arabinelli Nov 28 '20 at 16:10

abdulsaboor · Answer 2 · 2020-11-28T16:22:01.073

0

def remove_item(data):
    if type(data) is list:
        result = []
        for item in data:
            result.append(remove_item(item))
        return result
    elif type(data) is dict:
        data.pop(list(data.keys())[-1])
        return data
    return data

edited Nov 28 '20 at 16:22

answered Nov 28 '20 at 15:41

abdulsaboor

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TypeError: 'dict_keys' object is not subscriptable – Nov 28 '20 at 15:48
are you using python3? – abdulsaboor Nov 28 '20 at 16:22

adir abargil · Answer 3 · 2020-11-28T16:05:54.457

0

Here nice list comprehension in action:

  list_dicts = [dict(list(i.items())[:-1]) for i in list_dicts]

edited Nov 28 '20 at 16:05

answered Nov 28 '20 at 15:50

adir abargil

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TypeError: 'dict_items' object is not subscriptable – Nov 28 '20 at 15:51
We needto see exactly how your list look like because it makes no sense... – adir abargil Nov 28 '20 at 15:52
take this as example `[{'emptype': ['Manager'], 'Designation': ['Developer'], 'projecttype': ['temp']}]` – Nov 28 '20 at 15:53
I edited it , maybe try now... theissue i didnt cated the items to list... – adir abargil Nov 28 '20 at 16:06

score 0 · Answer 4 · answered Nov 28 '20 at 15:54

0

The basic operation for removing the last element of a dictionary mydict is mydict.pop(list(mydict)[-1]). If you have a list of dictionaries you can loop over them and apply the function to each dictionary.

mydict.keys()[-1] applies to python2

answered Nov 28 '20 at 15:54

Marc

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How to extract the element from the dictionary without last item

4 Answers4