Function errors in python

Question

I am studying python and when I was codding a simple calculator i found this error. Regardless of the function I call, the operation always adds up. Someone can help-me?

The code:

class CalculadoraTerminal:

# Addition

def addition(add, to_add):
    return add + to_add

# Subtraction

def subtraction(sub, to_sub):
    return sub - to_sub

# Multiplication

def multiplication(multi, to_multi):
    return multi * to_multi

# Division

def division(div, to_div):
    return div / to_div

# Menu

menu = input("A - Addition \nS - Subtraction \nM - Multiplication \nD - Division \nSelect you operation:")

if "A" == menu or "a":
    print(addition(int(input("Type the initial Number: ")), int(input("Type the number to add: "))))

if "S" == menu or "s":
    print(subtraction(int(input("Type the initial number: ")), int(input("Type the number to subtract: "))))

if "M" == menu or "m":
    print(multiplication(int(input("Type the initial number: ")), int(input("Type the number to multiply: "))))

if "D" == menu or "d":
    print(division(int(input("Type the initial  number: ")), int(input("Type the number to divide: "))))

Error example:

A - Addition S - Subtraction M - Multiplication D - Division Select you operation:d Type the initial Number: 20 Type the number to add: 2 22

``if menu == "A" or "a":`` does not do what you think it does. same for your other ``if`` statements — Mike Scotty, Dec 03 '20 at 20:18
`if menu == "A" or "a"` That is not the right way to check for multiple values. — John Gordon, Dec 03 '20 at 20:18

score 1 · Answer 1 · answered Dec 03 '20 at 20:19

1

The line if menu == "A" or "a": can be rewritten as if menu == "A" OR if 'a'.

If you want to check if menu is either "A" or "a", please do

if menu == "A" or menu == "a":

answered Dec 03 '20 at 20:19

Saddy

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Function errors in python

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