This question is answered at the following Stack Overflow link:
Wait for google server-side function to resolve
This question is specific to the google.script.run API for Apps Script.
I need to use a google.script.run.serverFncName() call to run code on the server, and then wait for the return before running the next function.
The code example that I am trying to convert, uses JavaScript fetch().then().
Example of code that I'm trying to convert:
<script>
  window.some_Object_Name = {
    innerNameOne : function() {
                   return fetch('The URL goes here for HTTP Request', {
                     method: 'post'
                   }).then(function(response_Back_From_Request) {
                     return res.json()response_Back_From_Request;
                   });
                },
  }
</script>
Need to use google.script.run.myServerAppsScriptFnc() instead of fetch(url)
Obviously, something like the following won't work, but I'm showing it for illustration purposes:
<script>
  window.some_Object_Name = {
    innerNameOne : function() {
                   google.script.run
                     .withSuccessHandler(function(response_Back_From_Request) {return response_Back_From_Request;})
                     .myServerAppsScriptFnc({method:'post'});
                   .then(function(response_Back_From_Request) {
                     return response_Back_From_Request;
                   });
                },
  }
</script>
I'm assuming that I'll need to use a Promise
<script>
  window.makeCallToGoogleServer = function() {
  
    google.script.run
      .withSuccessHandler(function(rtrnFromServer) {return rtrnFromServer;})
      .myServerAppsScriptFnc({method:'post'});
  }
  window.some_Object_Name = {
    innerNameOne : function() {
                   let myPromise = new Promise(function(myOnSuccessFnc) {
                     
                     makeCallToGoogleServer();
                       
                     myOnSuccessFnc(response_Back_From_Request);
                     
                   });
                myPromise.then(
                  return fromFirstFunc;
                 );
              }
  }
</script>
