7

In playwright-python I know I can get an elementHandle using querySelector().

Example (sync):

from playwright import sync_playwright

with sync_playwright() as p:
    for browser_type in [p.chromium, p.firefox, p.webkit]:
        browser = browser_type.launch()
        page = browser.newPage()  
        page.goto('https://duckduckgo.com/')
        element = page.querySelector('input[id=\"search_form_input_homepage\"]')

How do I get the an element relative to this based on this elementHandle? I.e. the parent, grandparent, siblings, children handles?

beginner
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buddemat
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2 Answers2

9

Original answer:

Using querySelector() / querySelectorAll with XPath (XML Path Language) lets you retrieve the elementHandle (respectively a collection of handles). Generally speaking, XPath can be used to navigate through elements and attributes in an XML document.

from playwright import sync_playwright

with sync_playwright() as p:
    for browser_type in [p.chromium, p.firefox, p.webkit]:
        browser = browser_type.launch(headless=False)
        page = browser.newPage()
        page.goto('https://duckduckgo.com/')
        element = page.querySelector('input[id=\"search_form_input_homepage\"]')
        
        parent = element.querySelector('xpath=..')
        grandparent = element.querySelector('xpath=../..')
        siblings = element.querySelectorAll('xpath=following-sibling::*')
        children = element.querySelectorAll('xpath=child::*')

        browser.close()

Update (2022-07-22):

It seems that browser.newPage() is deprecated, so in newer versions of playwright, the function is called browser.new_page() (note the different function name).

Optionally create a browser context first (and close it afterwards) and call new_page() on that context.

The way the children/parent/grandparent/siblings are accessed stays the same.

from playwright import sync_playwright

with sync_playwright() as p:
    for browser_type in [p.chromium, p.firefox, p.webkit]:
        browser = browser_type.launch(headless=False)
        context = browser.new_context()
        page = context.new_page()
        page.goto('https://duckduckgo.com/')
        element = page.querySelector('input[id=\"search_form_input_homepage\"]')
        
        parent = element.querySelector('xpath=..')
        grandparent = element.querySelector('xpath=../..')
        siblings = element.querySelectorAll('xpath=following-sibling::*')
        children = element.querySelectorAll('xpath=child::*')

        context.close()
        browser.close()
buddemat
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3

The Accepted answer is in older version of playwright.Use the following format for current version it will work.

from playwright.sync_api import sync_playwright

with sync_playwright() as p:
    for browser_type in [p.chromium, p.firefox, p.webkit]:
        browser = browser_type.launch(headless=False)
        context = browser.new_context()
        page =context.new_page()
        page.goto('https://duckduckgo.com/')
        element = page.query_selector('input[id=\"search_form_input_homepage\"]')
        
        parent = element.query_selector('xpath=..')
        grandparent = element.query_selector('xpath=../..')
        siblings = element.query_selector_all('xpath=following-sibling::*')
        children = element.query_selector_all('xpath=child::*')

        context.close()
        browser.close()
Mohanraj
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