Python input compared to list

Question

nums = [1, 2, 3, 4]

choice = input()

    if choice.isnumeric() and choice in nums:
        print("First")
   
    else:
        print("Second")

It prints out Second, can anyone explain why? I assume because it reads the number as a string since its input() rather than int(input()), and then it's false because list members are int, if that's the case, is it better to write the numbers in the list as strings, or is there another way to make it work?

Be careful with provided answers. You must handle the case where the input cannot be converted as a int. ```try/catch ValueError``` when casting it — Nic Laforge, Dec 26 '20 at 20:06

score 0 · Answer 1 · answered Dec 26 '20 at 20:02

0

you can cast choice to int after and:

nums = [1, 2, 3, 4]
choice = input()

if choice.isnumeric() and int(choice) in nums:
    print("First")
else:
    print("Second")

answered Dec 26 '20 at 20:02

Tugay

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score 0 · Accepted Answer · answered Dec 26 '20 at 20:02

I assume because it reads the number as a string since its input() rather than int(input()), and then it's false because list members are int

That's right. But you can convert input value to int to make it work:

if choice.isnumeric() and int(choice) in nums:
    print("First")

else:
    print("Second")

Python input compared to list

2 Answers2