How do I take a vector input using command line argument?

Question

I am not familiar with using command line arguments. I am trying to take a vector input as a command line argument. Please refer the below code and help me with the error.

#include<bits/stdc++.h>
#include<vector>

using namespace std;

int main(int argc, char *argv[]){
    vector<int> arr;
    cout<<"Arguments are:\n";
    for(int i = 1 ; i < argc ; i++){
        arr.push_back(argv[i]);
    }
    for(int i = 0 ; i < arr.size() ; i++){
        cout<<arr[i]<<" ";
    }
}

The code is giving below error.

You want to have `vector arr;` there, not `vector arr;`. Also stop doing [`#include`](https://stackoverflow.com/questions/31816095/why-should-i-not-include-bits-stdc-h) please. — πάντα ῥεῖ, Jan 01 '21 at 14:23
or a function (as [`std::stoi`](https://en.cppreference.com/w/cpp/string/basic_string/stol)) to convert the `char*` into `int`. — Jarod42, Jan 01 '21 at 14:26
Post error message as text first. (additional image/link might be fine). — Jarod42, Jan 01 '21 at 14:29
You can use the vector constructor: `vector arr(argv + 1, argv + argc);` instead of the loop — Thomas Sablik, Jan 01 '21 at 14:30

score 0 · Accepted Answer · edited Jan 01 '21 at 14:30

0

The problem is, that your vector contains ints, but the command line arguments are strings (see error). You should convert the argv[i] to int, than use the push_back(). You can use stoi() which converts string to int, but keep in mind that it could happen when not just digits appear in the command line argument.

edited Jan 01 '21 at 14:30

Enlico

23,259
6
48
102

answered Jan 01 '21 at 14:27

Geri Papp

28
8

How do I take a vector input using command line argument?

1 Answers1