How to get Assembly calculations in int format

Question

I'm still learning asm. im trying to find out why ax reg turns to 28 and not 25. I'm using emu8086.

mov dx,0h    ; dx = 0
mov ax,0050h ; ax = 50
mov bx,2     ; bx = 2
    
div bx ; ax / 2 =50.
       ; but ax is now 28?

Mind the `h` in `0050h`. Those are hex numbers, and `50/2 = 28` in hexadecimal. — dxiv, Jan 02 '21 at 23:44
Use your debugger to look at values; hopefully it shows them in both hex and decimal. Also, never use `div` to divide by 2: use `shr` by 1. — Peter Cordes, Jan 03 '21 at 11:22

gkhaos · Accepted Answer · 2021-01-02T23:49:29.247

4

Values in assembly are usually in hex, explicitly stated with the h at the of 0050h

50h or 0x50 is 80 in base 10
80/2=40
40 in hex is 0x28
therefore your result is 0x28 or 28h

edited Jan 02 '21 at 23:49

answered Jan 02 '21 at 23:48

gkhaos

1 Answers1