JS How do I get the value out of my method inside my function?

Asked Jan 06 '21 at 22:55

Active Jan 06 '21 at 23:06

Viewed 7 times

const getUserCoins = function(firstToUpper) {
    var getUserCoinsSql = `SELECT * FROM roulettetabelle WHERE Name = "${firstToUpper}"`
    
    con.query(getUserCoinsSql, function(err, result) {
        if (err) throw err;
        var resultString = JSON.stringify(result);
        var coinsPart = resultString.split(',"')[1]
        coins = parseInt(coinsPart.replace('Coins":', ""));
    });
}

Hello I want the function to return the value of coins... I dont understand how to do it

edited Jan 06 '21 at 23:06

asked Jan 06 '21 at 22:55

Tiqan

**WARNING**: Use placeholder values to inject data and stay away from template strings. Most MySQL Drivers for JavaScript support this out of the box. – tadman Jan 06 '21 at 23:24
Also consider using a Promise-capable database layer like [Sequelize](https://sequelize.org/master/). Then you can use `async`/`await` which makes your code easier to follow. – tadman Jan 06 '21 at 23:25

JS How do I get the value out of my method inside my function?

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