Creating Sub-lists Python3

Question

Say, I have this list: ['1', '1', '0', '1', '1', '1', '0', '0', '0', '0', '1', '0']

My expected output: [['1', '1', '0', '1'], ['1', '1', '0', '0'], ['0', '0', '1', '0']]

I got the expected output this way:

from collections import deque as de
a = '110111000010'
a = list(a)
que = de(a)
a = []
l = []
n = 0
while que:
    item = que.popleft()
    l.append(item)
    n += 1
    if n == 4:
        a.append(l)
        n = 0
        l = []
print(a)

I wanted to know is there a more efficient and simpler way to achieve this which can be described as elegant, understandable and most importantly pythonic.

You don't have to convert string to list. You can slice and dice the string just like a list. Hint: Use `range` to iterate through a chunk of the string and convert that chunk to a list to get the desired output. — Shiva, Jan 08 '21 at 11:23

score 0 · Accepted Answer · answered Jan 08 '21 at 11:23

def  func(arr, size):
    l = []
    for i in range(0, len(arr), size):
        l.append(arr[i:i+size])
    return l

arr = ['1', '1', '0', '1', '1', '1', '0', '0', '0', '0', '1', '0']
n = 4

sol = func(arr, n)
print(sol)

output

[['1', '1', '0', '1'], ['1', '1', '0', '0'], ['0', '0', '1', '0']]

Creating Sub-lists Python3

1 Answers1