Take as input N, the size of array. Take N more inputs - digits between 0 and 9 - and store that in an array. Take as input M, the size of second array and take M more input digits and store that in second array. Write a function that returns the sum of the numbers represented by the two arrays. Print the value returned.
Input:
4
1 0 2 9
5
3 4 5 6 7
Output:
3, 5, 5, 9, 6, END
Below is the code I have written for it, but it's not giving any result rather it crashes.
using namespace std;
int main()
{
int tsum,n,m,s,carry=0;
cin>>n;
int a[n],sum[]={0};
for(int i=0; i<n; i++)
{
cin>>a[i];
}
cin>>m;
int b[m];
for(int i=0; i<m; i++)
{
cin>>b[i];
}
s=max(n,m);
sum[s] = {0};
while(n>0 and m>0)
{
tsum=a[n]+b[m]+carry;
sum[s] = tsum%10;
carry = tsum/10;
n--;
m--;
s--;
}
if(n>m)
{
while(n>0)
{
tsum=a[n]+carry;
sum[s] = tsum%10;
carry = tsum/10;
n--;
s--;
}
}
if(m>n)
{
while(m>0)
{
tsum=b[m]+carry;
sum[s] = tsum%10;
carry = tsum/10;
m--;
s--;
}
}
for (int i=1; i<s; i++)
{
cout<<sum[i]<<", ";
}
cout<<"END";
return 0;
}```
