Find a set of keywords in a string

Question

def check_links(hrefs_list):
    check_str = ['NEWS',
                 'MEDIA',
                 'news',
                 'media',
                 'News',
                 'Media',
                 'press',
                 'releases',
                 'Press',
                 'Releases',
                 'PRESS',
                 'RELEASES']
    relevant_links=list()
    for i in range(len(hrefs_list)):
        if hrefs_list[i].find(check_str)!= -1:
            relevant_links.append(hrefs_list[i])
        else:
            continue
    return relevant_links

check_links(hrefs_list) accepts a list of href values. I want to go to each href value and check if it contains any of the keyword present in the check_str list. If it does, I want to store it to a fresh list, otherwise not. But when I run this function it gives an error : if hrefs_list[i].find(check_str)!= -1: TypeError: must be str, not list

How do I solve this ?

Could you edit the question to provide a sample ```hrefs_list``` and its expected output? — PSK, Jan 26 '21 at 08:58

score 0 · Answer 1 · answered Jan 26 '21 at 08:58

0

You should use this:

def check_links(hrefs_list):
    check_str = ['NEWS',
                 'MEDIA',
                 'news',
                 'media',
                 'News',
                 'Media',
                 'press',
                 'releases',
                 'Press',
                 'Releases',
                 'PRESS',
                 'RELEASES']
    relevant_links=list()
    for i in range(len(hrefs_list)):
        if hrefs_list[i] in check_str:
            relevant_links.append(hrefs_list[i])
        else:
            continue
    return relevant_links

Example:

hrefs_list = ['NEWS',
              'MEDIA',
              'news',
              'others']
check_links(hrefs_list)

Output:

['NEWS', 'MEDIA', 'news']

answered Jan 26 '21 at 08:58

itsDV7

854
5
12

1

for i in range(len(hrefs_list)): if any([x in hrefs_list[i] for x in check_str]) : relevant_links.append(hrefs_list[i]) – Soumya Pandey Jan 26 '21 at 09:26
used this and it works ! – Soumya Pandey Jan 26 '21 at 09:26
the code that you wrote will only work if it's an exact match. What if hrefs_list was ['www.example.com/news/', 'www.example.com/media-releases/', 'www.example.com/about-us'] then the code you wrote won't work. – Soumya Pandey Jan 26 '21 at 09:29

Find a set of keywords in a string

1 Answers1