Checking variable colors

Question

How can I get the following function to return multiple color types (not just red, but also orange, yellow, etc.) without using multiple if/else statements?

function isRainbowColor(color){
  if (color === "red"){
  return true;
  }else{
    return false;
  }
}
console.log(isRainbowColor("red"));
 //This returns true, but only for one color at a time.  How can I add onto ?

Create an Array of colors then test for `colorsArray.includes(argument)`. — StackSlave, Feb 04 '21 at 01:18

score 2 · Answer 1 · answered Feb 04 '21 at 01:17

2

Create an array of acceptable colors, and check the color with the Array.includes() function.

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes

function isRainbowColor(color){
  let acceptableColors = ["red","orange","yellow","blue","green"]
  if (acceptableColors.includes(color)){
  return true;
  }else{
    return false;
  }
}
console.log(isRainbowColor("red"));
console.log(isRainbowColor("green"));
console.log(isRainbowColor("purple"));
 //This returns true, but only for one color at a time.  How can I add onto ?

answered Feb 04 '21 at 01:17

symlink

11,984
7
29
50

1

how about just `return acceptableColors.includes(color)` ?? – Randy Casburn Feb 04 '21 at 01:19
1

@RandyCasburn I thought about changing it to that, but I didn't want to change up their code too much and possibly confuse them. – symlink Feb 04 '21 at 01:20
1

Yeah - I upvoted you anyway. The `if` statement simply serves no purpose, but I understand about confusing them. – Randy Casburn Feb 04 '21 at 01:22
1

Side note: you'd probably want `acceptableColors` to be `const` here – costaparas Feb 04 '21 at 01:48

Checking variable colors

1 Answers1