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I'm looking to generate a list of similar but different functions, within a for loop. A MWE (which doesn't achieve the goal) would be as follows:

def generic(a, n):
    return a + n

def make_funs():
    N = 5
    functions_out = []
    for n in range(N):
        functions_out += [lambda x : generic(x, n)]
    return functions_out

funs = make_funs

The goal would be that to get

funs[0]
> result = {function}
print(funs[0](1))
> 1
print(funs[2](1))
> 2

and so forth. The current code above returns 5 for any x I put into print(funs[x](1)), implying that all the functions in my funlist are being created with n = 4.

Note that this question is related to, yet meaningfully different from the question here. There, the lambda functions being creater only take one input variable, and so treats the x as I need to treat the n here. The desired output of that question is a list of numbers, my desired output is a list of functions.

Dan Goldwater
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  • [`from functools import partial`](https://docs.python.org/3/library/functools.html#functools.partial) … `functions_out.append(partial(generic, n=n))` – deceze Feb 05 '21 at 11:22
  • Did you mean: `functions_out.append(lambda x, n=n : generic(x, n))`? – quamrana Feb 05 '21 at 11:23

0 Answers0