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{i:1, j:2, k:3} return (1,2,3) How can you do this?

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6 Answers6

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 dictionary = {'A':True, 'B':False, 'C':True, 'D':False} 
 my_list = [key for key in dictionary.keys() if dictionary[key]]
Kraigolas
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Try this:

dict_ = {'A':True, 'B':False, 'C':True, 'D':False} 
keys = [key for key, value in dict_.items() if value]
sarartur
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By this list compression, you can get the specific keys which value is true

[i for i,j in a.items() if j]
Sohaib Anwaar
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You could use a list comprehension like this:

D = {'A':True, 'B':False, 'C':True, 'D':False}

L = [k for k in D if D[k]] # ['A', 'C']
Alain T.
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Setting up the data

my_dictionary = {'A':True, 'B':False, 'C':True, 'D':False}

Now go through the dictionary and add it to the list if the dictionary key is True

my_list = [i for i in my_dictionary if my_dictionary[i]]

Which gives

['A', 'C']
Paul Brennan
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dror_python_encoder
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Another way would be to use filter -


D = {'A':True, 'B':False, 'C':True, 'D':False}

>>> list(filter(lambda x: D[x],D))
['A', 'C']
Vaebhav
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