How to sort array in Node.js by attribute and alphabetically

Question

I don't know exactly how to explain it, but this is what I want. I have an array of domains also containing a health value and this is how I want to sort it. If the health value is unknown, currently healthKnown is set to false and health is set to 95.

aaa.com - 100
bbb.com - 100
ccc.com - 100
aaa.com - 90
bbb.com - 90
ccc.com - 90
aaa.com - (unknown)
bbb.com - (unknown)
ccc.com - (unknown)

(there wouldn't be any duplicates though)

In this, each set of domains with the same health are alphabetically sorted and unknown health is last. The array looks like this.

[
  {
    "name": "example1.com",
    "details": ...,
    "health": 100,
    "healthKnown: true
  },
  {
    "name": "example2.com",
    "details": ...,
    "health": 100,
    "healthKnown: true
  }
]

you need to use [`array.sort()`](https://devdocs.io/javascript/global_objects/array/sort) — Manuel Spigolon, Feb 26 '21 at 09:18

lcapra · Answer 1 · 2021-03-01T14:53:58.220

1

as per comments, array.sort() is probably the best way to go. See an example

let domains = [
  {
    "name": "a.example1.com",
    "details": "",
    "health": 100,
    "healthKnown": true
  },
  {
    "name": "c.example2.com",
    "details": "",
    "health": 100,
    "healthKnown": true
  },
  {
    "name": "b.example2.com",
    "details": "",
    "health": 100,
    "healthKnown": true
  }
]

domains
  .sort((a,b) => b.healthKnown && a.health > b.health ? 1 : -1)
  // credits to https://stackoverflow.com/a/61033232/833499
  .sort((a, b) => a.name.localeCompare(b.name))
console.log(domains);

edited Mar 01 '21 at 14:53

answered Feb 26 '21 at 09:47

lcapra

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16
18

That does sort it correctly by health, but it doesn't sort it alphabetically as well. – Jacob Feb 26 '21 at 20:27
It's just an example. Add a subsequent .sort() ordering by name and you are done – lcapra Feb 28 '21 at 07:03

How to sort array in Node.js by attribute and alphabetically

1 Answers1