Start process and get its output constantly

Question

I have a console program written in c++, and I would like to continually check its output to use in my c# project.

This is the code I've tried to steal from another StackOverflow question, but with no luck.

Edit:( By no luck, I mean: the output is pretty much empty, although if I set p.StartInfo.CreateNoWindow to false, I can see my script.exe launch and output into its window. )

    Process p = new Process();
    p.StartInfo.FileName = @"external\script.exe";
    p.StartInfo.UseShellExecute = false;
    p.StartInfo.RedirectStandardOutput = true;
    p.StartInfo.CreateNoWindow = true;
    p.Start();

    string output = p.StandardOutput.ReadToEnd();
    p.WaitForExit();

    Console.WriteLine("Output:");
    Console.WriteLine(output);

What do you mean "with no luck"? What is the observed behavior? What does it do? What do you want it to do instead? — mason, Mar 02 '21 at 16:28
@ΦXocę 웃 Пepeúpa, It is pritning (or writing into its console) — Ghost, Mar 02 '21 at 16:29
@mason the output is pretty much empty altough if i set p.StartInfo.CreateNoWindow to false, i can see my script.exe launch and output into its own window. — Ghost, Mar 02 '21 at 16:31
Does it need to be in C#? This would be a lot simpler to do in Powershell? — Liam, Mar 02 '21 at 16:53
You're identified your code as c++. It's not. See [How similar are c# and c++?](https://stackoverflow.com/a/6997295/2791540) — John Wu, Mar 02 '21 at 18:44

score 0 · Answer 1 · answered Mar 02 '21 at 18:35

I had a similar issue and it had to do with where the output was going. The solution was to run cmd and execute my script from the cmd process. See this answer to another question for more information. reading from stdout and stderr together Your new code would look like:

    Process p = new Process();
    p.StartInfo.FileName = "cmd.exe";
    p.StartInfo.Arguments = "/c yourscriptpath.exe 2>&1";
    p.StartInfo.UseShellExecute = false;
    p.StartInfo.RedirectStandardOutput = true;
    p.StartInfo.CreateNoWindow = true;
    p.Start();

    string output = p.StandardOutput.ReadToEnd();
    p.WaitForExit();

    Console.WriteLine("Output:");
    Console.WriteLine(output);

Start process and get its output constantly

1 Answers1