Python code not displaying the list values each in a new line no matter how hard I try

Question

I've written a code which works pretty well, no errors, no problems. But no matter how hard I try to print the list values each in a new line, it still wouldn't work. I've tried sep='\n', and even tried to put the list in a loop to print each value one by one. I still get the result printed all in a row, in one line. This sounds too annoying and I can't figure out why my code is having this strange behavior. Here's my code:

length = int(input())
input_string = [int(y) for y in input().split()]

def lowest(string):

    return(min(x for x in string if x is not None))

def none_set(string):
    for k in range(length):
        if string[k] != None:
            if string[k] <=0:
                string[k] = None

def counter(string):
    nums = 0
    for h in range(length):
        if string[h] != None:
            nums += 1

    return nums

cnt = []

for i in range(length):   
    minimum = lowest(input_string)
    none_set(input_string) 
    
    cnt.append(counter(input_string))

    for j in range(length):
        if input_string[j] != None:
            input_string[j] -= minimum
        
result = list(set(cnt))[::-1]
print(result, sep='\n') #Doesn't print the values in new line :/

Sample Input:

6
5 4 4 2 2 8

Expected Output:

The Output I Get:

[6, 4, 2, 1]

In case you want to know what exactly my code does, check this link here (No login/signup needed), however, the issue is not really relative to what the goal of my code is, I'd say.

I appreciate in advance, for any tip, solution, or help.

Does this answer your question? [Printing list elements on separated lines in Python](https://stackoverflow.com/questions/6167731/printing-list-elements-on-separated-lines-in-python) — Gino Mempin, Mar 07 '21 at 23:52

score 1 · Answer 1 · answered Mar 07 '21 at 17:24

1

It's because you're printing the whole list.

lst = ['a','b','c']

If I print this list I get ['a','b','c']. To print each item you can use a for loop like so:

lst = ['a','b','c']

for item in lst:
    print(item)

#output: 
a
b
c

answered Mar 07 '21 at 17:24

Have a nice day

1,007
5
11

Right, but why does ```sep='\n'``` work then? – Mar 07 '21 at 17:27
oops, my bad, yes, I meant why does ```sep='\n'``` NOT work. – Mar 07 '21 at 17:38
Gotcha. Well @Eitan Rosati Explained it for you I see :). Have a nice day! – Have a nice day Mar 07 '21 at 17:46

score 0 · Answer 2 · edited Mar 07 '21 at 17:26

0

Try to print like that:

for i in result:
    print(i)

edited Mar 07 '21 at 17:26

Chris

15,819
3
24
37

answered Mar 07 '21 at 17:24

Eitan Rosati

543
5
18

Thank you :)) Now it works. But I still don't understand why ```sep='\n'``` would not work. Is it not supposed to be used in such cases? – Mar 07 '21 at 17:28
Because when you print a list he consider the list as one object. – Eitan Rosati Mar 07 '21 at 17:32
Ah, got it. Thank you:)) – Mar 07 '21 at 17:36
List have a default function to show him as a string. because list like any other data structer in python is an well defind object – Eitan Rosati Mar 07 '21 at 17:39

score 0 · Answer 3 · answered Mar 07 '21 at 17:25

0

Try this.

 for i in result:
     print(i)

answered Mar 07 '21 at 17:25

Kevin G

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15

score 0 · Answer 4 · answered Mar 07 '21 at 18:17

Use join() instead of multiple calls to print(). Some will consider it more difficult to read, but it's definitely more efficient even for small lists, and orders of magnitude faster for lists greater than 100 elements.

print("\n".join(map(str, result)))

Python code not displaying the list values each in a new line no matter how hard I try

4 Answers4