How to replace nth occurrence in the xml template in Java?

Question

Here I am doing automation with Java, serenity with rest-assured. So I want to replace the 2nd  &  tags with a blank string.

Here I attached the template

<Request>    
    <P>
        <n>name1</n>
        <v>${value1}</v>
    </P>
    <P>
        <n>name2</n>
        <v>${value2}</v>
    </P> 
   <P>
        <n>name3</n>
        <v>value3</v>
    </P> 
</Request>

I am using the below code to replace the 2nd  and  tags. But it was replaced the all  & tags(first and last  &  tags also)

String request = exampleTemplate.replace("${value1}", "XYZ")
                .replace("<P>", "")
                .replace("<v>${value2}</v>", "1234")
                .replace("</P>", "")
                .replace("${value3}", "AAA");

How can I replace only the 2nd  and  tags?

score 2 · Accepted Answer · answered Mar 23 '21 at 15:16

2

You can match both the first and second  elements together.

String res = str.replace("${value1}", "XYZ")
                .replace("<v>${value2}</v>", "1234")
                .replace("${value3}", "AAA")
                .replaceFirst("(?s)(<P>.*?</P>\\s*)<P>(.*?)</P>", "$1$2");

Demo

answered Mar 23 '21 at 15:16

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Thanks for the regular expression. Is there any way to replace last '
' & '
' tags.? – kithmi Mar 24 '21 at 04:43
2

This is a very intelligent way of using regex for this solution. @kithmi - you can learn more about regex from [Learning Regular Expressions](https://stackoverflow.com/q/4736/10819573). However, I suggest you try solving these kinds of problems using an XML parser. – Arvind Kumar Avinash Mar 24 '21 at 11:31

How to replace nth occurrence in the xml template in Java?

1 Answers1