I'm trying to write an expression parser. One part I'm stuck on is breaking down an expression into blocks via its appropriate order of precedence.
I found the order of precedence for C++ operators here. But where exactly do I split the expression based on this?
I have to assume the worst of the user. Here's a really messy over-exaggerated test example:
if (test(s[4]) < 4 && b + 3 < r && a!=b && ((c | e) == (g | e)) ||
r % 7 < 4 * givemeanobj(a & c & e, b, hello(c)).method())
Perhaps it doesn't even evaluate, and if it doesn't I still need to break it down to determine that.
It should break down into blocks of singles and pairs connected by operators. Essentially it breaks down into a tree-structure where the branches are the groupings, and each node has two branches.
Following the order of precedence the first thing to do would be to evaluate the givemeanobj(), however that's an easy one to see. The next would be the multiplication sign. Does that split everything before the * into a separate , or just the 4? 4 * givemeanobj comes before the <, right? So that's the first grouping?
Is there a straightforward rule to follow for this?