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I sorted my list using seq.sort(key = lambda x: x[1]) into [[4, 0], [8, 0], [1, 0], [10, 0], [2, 2], [0, 2], [3, 3], [6, 3], [7, 3], [9, 3], [5, 4]], but i want it reversed like this [[5, 4], [9, 3], [7, 3], [6, 3], [3, 3], [0 , 2], [2 ,2], [10, 0], [1, 0], [8, 0], [4, 0]]. I've tried doing this seq = seq[::-1] , but doesn't work. It works if i store it in a new list new_list = seq[::-1], but i want to use the same list seq.

Ruben Gavris
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    `seq = seq[::-1]` should work. – xjcl Mar 31 '21 at 20:40
  • What do you mean new list? I believe with seq[::-1] you are only getting a new reference, not a deep copy of the existing list. – Anthony O Mar 31 '21 at 20:41
  • Does this answer your question? [Python list sort in descending order](https://stackoverflow.com/questions/4183506/python-list-sort-in-descending-order) `list.sort()` takes a boolean `reverse` argument – Pranav Hosangadi Mar 31 '21 at 20:42
  • Seems you’re trying to reverse the list not sort it – Jab Mar 31 '21 at 20:43

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Look at this link

You were on a good path with the sort() function, but the sort function just has an extra 'reverse' parameter which is False by default. Your code should be seq.sort(key = lambda x: x[1], reverse=True)

Xander
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