Scanner.nextLine() sending data but won't compare it inside of a function

Question

Trying to take data from scanner and pass it to a function that compares that data to an array, but when I send the data that the scanner receives it won't compare.

Scan class

Key.use(scan.nextLine().toString(), retrievedkey);

Key function that iterates through the array to compare the first parameter to the arraylist

public static void use(String door, String[][] key){
        var arraylength = key[1].length;
        for (int i = 0; i<=arraylength;){
            i++;
            if (door == key[1][i]) {
                canOpen = true;
                System.out.println(canOpen);
            }
            else {
                canOpen = false; 
                System.out.println(canOpen + " " + door + " " + Arrays.toString(key[1]));
            }
            return;
        }
        
    }
    
}

When sending data separately from the scan function the key function works. Ex:

Key.use("Front door", retrievedkey)

But the scanner prints the input as "door" yet isn't read by the function. Any help? Thanks.

Java uses methods, not functions. Also, that's an array, not ArrayList. — ublec, Apr 17 '21 at 03:48
The following lines also seem wrong: `var arraylength = key.length; // rows` `for(int i = 0; i < arraylength; i++) {` `if(door.equals(key[0][i])) { // arrays in Java are zero indexed`. — Kaplan, Apr 17 '21 at 07:22

score 0 · Accepted Answer · answered Apr 17 '21 at 02:15

            if (door == key[1][i]) {
                canOpen = true;
                System.out.println(canOpen);
            }

You should use

if (door.equals(key[i][1]))

instead of

if (door == key[1][i])

And there is no need to use toString() method in

Key.use(scan.nextLine().toString(), retrievedkey);

since nextLine() reads String as input.

Scanner.nextLine() sending data but won't compare it inside of a function

1 Answers1