Creating 100 variables

Question

So I created an array with 100 variables using Enumerable.Range. The data type is limited to Int32.

Problem

How can I create the same array with SByte?
Am I right in thinking I would need to use a loop to create and index the variables?

I have looked around online and most results touch on declaring counting variables for the loop but not using a loop to declare variables

_"So I created an array with 100 variables using enumerable range [...] How can I create the same array with sByte?"_ Well... exactly the same way, but change `int` to `sbyte`. — RobIII, Apr 28 '21 at 08:46
You wouldn't use a loop to declare variables. You can use a loop to add elements to an array. Maybe the mix-up in terminology is causing problems with your searching? — canton7, Apr 28 '21 at 08:47
`Enumerable.Range(1, 100).Select(n => (sbyte)n).ToArray()`. But this does not create 100 *variables*, but an array of 100 *values*. — Klaus Gütter, Apr 28 '21 at 08:50

Tim Schmelter · Accepted Answer · 2021-04-28T09:08:23.293

1

Just cast them:

SByte[] array = Enumerable.Range(0, 100).Select(i => (SByte) i).ToArray();

note that SByte is not cls compliant, you might want to use short instead.

edited Apr 28 '21 at 09:08

answered Apr 28 '21 at 08:52

Tim Schmelter