Split a string in Python dictionary with two different separators only if the separator exist on the string

Question

I have a dictionary :

{'...': '...',
'unite_fonctionnelle': 'text to keeep',
'...': '...'}

In this case the dictionary is good but sometimes the value of unite_fonctionnelle need to be cleaned, the syntaxe is always the same:

{'...': '...',
'unite_fonctionnelle' : 'asjbzjqnfknqfsnf<Run>text to keeep</Run>qsdqsdqsdqsfqsfegdhfkdnh',
'...': '...'}

I want to transform the value of unite_fonctionnelle when tags <Run> and </Run> are present in the string to keep only the text between the two tags. How can I do this with split() ?

See: https://stackoverflow.com/questions/3368969/find-string-between-two-substrings. — sander, May 06 '21 at 15:21

score 2 · Accepted Answer · answered May 06 '21 at 15:44

2

You can simply use regex here.

Try this :

import re

for key, value in dic.items():
    if '<Run>' in str(value):
        output = re.search('<Run>(.*)</Run>', str(value))
        print(output.group(1))

answered May 06 '21 at 15:44

Keyur Shrimali

64
4

Thanks, I adapt it to my code and it works perfectly! – Howins May 06 '21 at 16:16
Welcome :) @Howins – Keyur Shrimali May 06 '21 at 17:12

score 1 · Answer 2 · answered May 06 '21 at 15:30

1

Given d your dictionary:

for k, v in d.items():
    if '<Run>' in v:
        d[k] = v.split('<Run>')[1].split('</Run>')[0]

answered May 06 '21 at 15:30

Synthase

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2
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score 0 · Answer 3 · answered May 06 '21 at 15:55

This is my approach.

import re
dic = {
'unite_fonctionnelle' : 'asjbzjqnfknqfsnf<Run>text to keeep</Run>qsdqsdqsdqsfqsfegdhfkdnh'
}
for key,val in dic.items():
    if(all(x in val for x in ['<Run>','</Run>'])):dic[key] = re.split('<Run>|</Run>',val)[1]

Split a string in Python dictionary with two different separators only if the separator exist on the string

3 Answers3