fgets() is not getting input

Question

fgets() is skipping and not taking input. How can I solve it? I've tried using a scanf(), but scanf() is taking input upto the first space. I want to take a input such as: Steve Jobs

#include<stdio.h>
int main()
{
    // ints
    int age;
    printf("Enter your age: ");
    scanf("%d", &age);
    printf("You are %d \n", age);

    // chars
    char grade;
    printf("Enter your grade: ");
    scanf(" %c", &grade);
    printf("You got an %c on the test \n", grade);

    // doubles
    double gpa;
    printf("Enter your gpa: ");
    scanf("%lf", &gpa);
    printf("Your gpa is %lf \n", gpa);

    // strings
    char name[20];
    printf("Enter your name:");
    fgets( name, 20, stdin);  // this line is not working
    printf("Hello %s! \n", name);


    return 0;
}

Does this answer your question? [fgets doesn't work after scanf](https://stackoverflow.com/questions/5918079/fgets-doesnt-work-after-scanf) — yano, May 17 '21 at 14:12
http://sekrit.de/webdocs/c/beginners-guide-away-from-scanf.html — William Pursell, May 17 '21 at 14:30
Use `fgets()` only for clean input. Use `scanf()` to continue having problems. — chux - Reinstate Monica, May 17 '21 at 17:47

score 4 · Accepted Answer · answered May 17 '21 at 14:25

4

this:

scanf("%lf", &gpa);

left a newline \n in stdin

this:

fgets( name, 20, stdin);

stops inputting after consuming the newline \n

You might want to learn about character sets, similar to:

scanf( "%19[^\n]", name );

or simply calling: getchar() before calling fgets()

answered May 17 '21 at 14:25

user3629249

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using scanf("%19[^\n]", name); is not working.. – Abir Hasan Arko May 17 '21 at 15:48
sorry, there should be a space before the character set, as in: `" %[^\n]"` The leading space consumes any leading `white space` like the newline – user3629249 May 17 '21 at 19:37

fgets() is not getting input

1 Answers1