Python, Selenium: how to refresh page until element is present

Question

while True:
    try:
        browser.find_element_by_xpath('//*[@id="layoutPage"]/div[1]/div/div/div[3]/div[4]/div[2]/div/section/div[1]/div/button/div')
        break
    except NoSuchElementException:
        browser.refresh()

Why do I still get selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id="layoutPage"]/div[1]/div/div/div[1]/div/div[1]/button[2]"} eroor? I have imported the NoSuchElementException from selenium.common.exceptions.

Already been answered. https://stackoverflow.com/questions/10245641/refreshing-web-page-by-webdriver-when-waiting-for-specific-condition — saty035, May 25 '21 at 12:36
@MikaelMikaelian what exactly element are you trying to locate there? — Prophet, May 25 '21 at 13:22
@Prophet The green button that will apper Like here HTML: https://dropmefiles.com/tKq7P — Mikael Mikaelian, May 25 '21 at 13:37
I see. I can build the Xpath according to the text. It's not the best practice, but much better than your expression... — Prophet, May 25 '21 at 13:51
Can you also add the similar HTML for non-empty page there for that button disabled? Or you just trying to catch that button appearing? — Prophet, May 25 '21 at 13:52

Prophet · Accepted Answer · 2021-05-25T12:56:46.073

4

Try

while True:
    try:
        browser.find_element_by_xpath('//*[@id="layoutPage"]/div[1]/div/div/div[3]/div[4]/div[2]/div/section/div[1]/div/button/div')
        break
    except:
        browser.refresh

or maybe this:

while True:
    if(browser.find_elements_by_xpath('//*[@id="layoutPage"]/div[1]/div/div/div[3]/div[4]/div[2]/div/section/div[1]/div/button/div')):
        break
    else:
        browser.refresh

Pay attention, I'm using find_elements in the second code. It returns list. In case the list is non-empty it should enter the if else it will go into else and refresh the page

edited May 25 '21 at 12:56

answered May 25 '21 at 12:36

Prophet

32,350
22
54
79

I updated the code. It should be `browser.refresh`, without the `()` – Prophet May 25 '21 at 12:47
Did not help. `selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id="layoutPage"]/div[1]/div/div/div[1]/div/div[1]/button[2]"}` – Mikael Mikaelian May 25 '21 at 12:50
Is there any other way I can refresh the page until the element is present? – Mikael Mikaelian May 25 '21 at 13:03
Yes, but what I suggested should work too. So first of all I can't understand why it doesn't work for you – Prophet May 25 '21 at 13:06
1

Check manually if your locator is the same after each refresh. – vitaliis May 25 '21 at 13:18
So it worked finally? What was the problem? – Prophet May 27 '21 at 13:16

Indian Gamex · Answer 2 · 2021-05-27T12:49:51.093

you can use time.sleep() command after refreshing see if it works,

i guess it will because it instantly analyses the page after refreshing, because of which the page doesn't get time to fully load itself and throws error to you as it doesn't get the desired thing which it is searching for !

hope it helps !!!

while True:
    element = browser.find_elements_by_xpath('//*[@id="layoutPage"]/div[1]/div/div/div[3]/div[4]/div[2]/div/section/div[1]/div/button/div')
    if element != None:
        print("got it !")
        break
    else:
        browser.refresh()
        time.sleep(2)
        continue

or

for i in range(1):
    while True:
    element = browser.find_elements_by_xpath('//*[@id="layoutPage"]/div[1]/div/div/div[3]/div[4]/div[2]/div/section/div[1]/div/button/div')
    if element != None:
        print("got it !")
        break
    else:
        browser.refresh()
        time.sleep(2)
        continue

Unfortunately, did not help. – Mikael Mikaelian May 25 '21 at 12:59 — Mikael Mikaelian, May 25 '21 at 12:59

Python, Selenium: how to refresh page until element is present

2 Answers2