You must write local service. But be carefull for security.
- Web Site (HTML)
- Local App Run Program ( exe file: listened on 8001 )
Algorithm
**Example HTML Call **
<button>Run Program</button>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js" integrity="sha512-894YE6QWD5I59HgZOGReFYm4dnWc1Qt5NtvYSaNcOP+u1T9qYdvdihz0PPSiiqn/+/3e7Jo4EaG7TubfWGUrMQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
<script>
$("button").click(function(){
  $.get("//localhost:8001", function(data, status){
    alert("Data: " + data + "\nStatus: " + status);
  });
});
</script>
Example App Run Program
# Python 3 server example
from http.server import BaseHTTPRequestHandler, HTTPServer
import time
import subprocess
hostName = "localhost"
serverPort = 8001
class MyServer(BaseHTTPRequestHandler):
    def do_GET(self):
        self.send_response(200)
        # IMPORTANT ENABLE HERE CORS 
        self.send_header("Content-type", "text/html")
        self.end_headers()
        self.wfile.write(bytes("<ok>Run Start Program</ok>", "utf-8"))
        # CHANGE HERE
        subprocess.call(['C:\\Temp\\a b c\\Notepad.exe', 'C:\\test.txt'])
if __name__ == "__main__":        
    webServer = HTTPServer((hostName, serverPort), MyServer)
    print("Server started http://%s:%s" % (hostName, serverPort))
    try:
        webServer.serve_forever()
    except KeyboardInterrupt:
        pass
    webServer.server_close()
    print("Server stopped.")