python string variable changes '\b' into '\x08' and '\a' into '\x07' and similarly for some number and characters too? why?

Question

When I am using filename="media\documents\dog_bark.wav" Python works fine and my intended functionality works.

But with filename="media\documents\afile1.wav", filename="media\documents\732-20.wav" and similar other selected filepaths it's changing the first character of the filename to \x07, I have also seen \x08 and so on

Why does this happen and is there any solution for this?

Always use raw strings (`r'...'`) when dealing with backsplashes in strings. — Klaus D., Jun 12 '21 at 06:04
It is better to use forward slashes for a [Windows path in Python](https://stackoverflow.com/questions/2953834/windows-path-in-python) anyway. — Karl Knechtel, Aug 07 '22 at 04:00

kantrveysel · Answer 1 · 2021-06-12T06:13:21.420

0

Are you using like that "media\\documents\\afile1.wav" , right? with double \

"media\documents \afile1.wav" \a is a char

"media\documents \732-20.wav" \7 is a char also

when you use \d it is not a char so it changing to \\d in a string

you can use r" RAW STRING " if you do not want to care about it.

edited Jun 12 '21 at 06:13

answered Jun 12 '21 at 06:07

kantrveysel

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python string variable changes '\b' into '\x08' and '\a' into '\x07' and similarly for some number and characters too? why?

1 Answers1