How to capture string using regex

Question

My current regex query is

    (?P<TestName>(?<=_)[^\s]+)

Its able to capture "ABCD" and "Adjust_Path". I would like to capture the string "LED" as well from the list below

    4039_ABCD
    LED
    2020_Adjust_Path

With the samples shown, maybe `^(?:\d+_)?(?P\w+)` will do – JvdV Jun 16 '21 at 06:47 — JvdV, Jun 16 '21 at 06:47
in which language you are doing regex query – Chandra Mochahary Jun 16 '21 at 06:52 — Chandra Mochahary, Jun 16 '21 at 06:52

score 0 · Answer 1 · answered Jun 16 '21 at 07:56

0

(?<=_)[^\s]+)|((?!.*_)[^\s]+)

| : for the 2 cases (alternatives)

(?!.*_) : second case : not every string with a _

More info

answered Jun 16 '21 at 07:56

Dri372

The fourth bird · Accepted Answer · 2021-06-16T08:15:40.450

You might assert an underscore to the left, and match any char except a whitespace char or underscore till the end of the string.

(?P<TestName>(?<=_)\S+|[^\s_]+)$

The pattern matches:

(?P<TestName> Named group TestName
- (?<=_) Positive lookbehind, assert _ directly to the left
- \S+ Match 1+ times a non whitespace char
- | Or
- [^\s_]+ Match 1+ times any char except _ or a whitespace char
) Close group TestName
$ End of string

If there has to be a digit present before the underscore:

(?P<TestName>(?<=\d_)\S+|[^\s_]+)$

2 Answers2