php function returns "Warning: Array to string conversion in"

Question

I have the following PHP function where I am trying to explode an array and apply foreach loop on it to get a collective set of data. However, I am getting the error quoted in the subject.

function getSwipableUsers() {
  $expInt = explode(',', $f['interests']);

  $userDisplayData = array();
  foreach($expInt as $ints){
    $userDisplayData[] = "<div class='tag alert-primary'>".$ints."</div>";
  }

  $html = '<div class="user-distance mt-2">'.$userDisplayData.'</div>';
  return $html;
}

I rechecked again and again but everything seems fine to me. What's wrong with my code here?

`$userDisplayData` is an array which you try to string concatenate in `$html = '
'.$userDisplayData.'
';` — Remy, Jun 19 '21 at 15:50
You could define `$userDisplayData` as a string and concatenate those divs to it or use [implode](https://www.php.net/manual/en/function.implode.php) with an empty string separator to convert the array to a string. — Remy, Jun 19 '21 at 15:52
Instead of pushing `"
".$ints."
"` to `$userDisplayData[]`, concatenate these strings to `$html` directly or else re-iterate the `$userDisplayData` and append all strings to `$html` — Haridarshan, Jun 19 '21 at 15:55
@Haridarshan if you see my comment right above yours, I actually figured it out. But thanks for your time :) — Shubham Jha, Jun 19 '21 at 16:34

score 1 · Accepted Answer · edited Jun 21 '21 at 07:48

1

As stated above, the $userDisplayData variable is an array, and you are trying to assign a string space to it.

You could do it this way:

function getSwipableUsers() {
    $expInt = explode(',', $f['interests']);
  
    $userDisplayData = '<div class="tagsection">';

    foreach($expInt as $ints){
      $userDisplayData .= "<div class='tag alert-primary'>".$ints."</div>";
    }

    $userDisplayData .= '</div>';

    $html = '<div class="user-distance mt-2">'.$userDisplayData.'</div>';

    return $html;
}

edited Jun 21 '21 at 07:48

Shubham Jha

97
10

answered Jun 19 '21 at 15:59

Nícollas Silva

116
3

1

I already figured it out after @Remy hinted about concatenating. But accepting your answer to let others know that this is the right approach which I used. – Shubham Jha Jun 19 '21 at 16:36

php function returns "Warning: Array to string conversion in"

1 Answers1