Creating an alarm in seconds Python

Question

I am trying to code a function that recognizes when X amount of seconds has passed without pausing the program, so without using time.sleep. How would I be able to do that by using the unix timestamp? So for the code below it would print 5 seconds has passed for every 5 seconds that passes.

import time
X = 5
TIME = time.time()

You should use threads in order to continue the program without stopping the main thread. — scmanjarrez, Jun 24 '21 at 16:45
Does this answer your question? [Python threading.timer - repeat function every 'n' seconds](https://stackoverflow.com/questions/12435211/python-threading-timer-repeat-function-every-n-seconds) — scmanjarrez, Jun 24 '21 at 16:45

score 0 · Answer 1 · answered Jun 24 '21 at 17:20

Check this will help you avoid using time.sleep() and your code will be iterating till the time reaches next X seconds

import time
startTime = time.time()
X = 5
timeDif = 0
while timeDif < X:
    currentTime = time.time()
    timeDif = currentTime - startTime

Creating an alarm in seconds Python

1 Answers1