Python if statement gone wrong. Whats wrong?

Question

I don't understand what's wrong with my code here. Can someone help me pls? I've been trying to solve it all morning.

question = input("Choose from 0 to 1 : ") 
mylist = ["Mark", "Jenny"] 
if question == 0: 
    print(mylist[0], "is your new friend") 
elif question == 1: 
    print(mylist[1], "is your new friend")
else:
    print("I said choose from 0 to 1")

The input() function returns a string, but you are checking against integers 0 and 1. — JiyuuSensei, Jul 07 '21 at 08:45

Geom · Answer 1 · 2021-07-07T08:45:46.970

1

The problem is in the data types:

input() returns a string but in your, if statement you're comparing a string "0" to an integer 0. Because of that else is always executed.

Concert the input() into int() like shown below:

question = int(input("Choose from 0 to 1 : "))
mylist = ["Mark", "Jenny"] 
if question == 0: 
    print(mylist[0], "is your new friend") 
elif question == 1: 
    print(mylist[1], "is your new friend")
else:
    print("I said choose from 0 to 1")

edited Jul 07 '21 at 08:45

answered Jul 07 '21 at 08:43

Geom

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Im stupid I guess. I should have seen it. Thank you – Nektarios Kouromichelakis Jul 07 '21 at 08:45
happens with everyone, This is how you remember these things after countless times making this mistake! – Geom Jul 07 '21 at 08:50

Python if statement gone wrong. Whats wrong?

1 Answers1