Why 10.5 become 10.0 after swap ?
#define swap(a,b) {int aux; aux=a; a=b; b=aux;}
float x=10.5, y=3.75;
swap(x,y);
// x=3.75, y=10.0;
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Caleb
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Madison John
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What would you expect to happen if you called `swap(1.5,2.5)`? – Scott Hunter Jul 12 '21 at 18:11
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2change int aux to float aux. you are storing float value in int variable. – Harshal Jul 12 '21 at 18:11
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1You may be interested in: https://stackoverflow.com/a/20380289/459640 – aschepler Jul 12 '21 at 18:44
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aux is of type int, which will drop the decimal part of the argument a passed to swap. In this case, swap(x, y) drops the decimal part of x before it is assigned to y at the end.
StardustGogeta
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