Terminate Python program if input isn't specified in due timeframe

Question

I'm trying to terminate python program if an input isn't provided by user within specific time frame, say - 5 seconds.

The code has been taken and edited from mediocrity's answer

import sys
import time
from threading import Thread

x = None

def check():
    global x
    time.sleep(5)
    if x:
        print("Input has been given!")
        return
    sys.exit()

Thread(target=check).start()
x = input("Input something: ")

But it keeps waiting for the input and doesn't terminate, unless the input is given. How could I change the code so that it executes as inteded?

Did you read the comments below the answer that you copied? They say that it doesn't work. — Barmar, Jul 16 '21 at 20:51
I've tried that solution, it terminates process immediately without a delay. The output is ```You have 5 seconds to type in your stuff... You typed None``` — The August Georgian, Jul 16 '21 at 20:54
I'd also like to see if it could be done with threads and the code I supplied. — The August Georgian, Jul 16 '21 at 20:56
Actually, if you want to terminate the whole script, I think your original code should work. I'm not sure why it doesn't. — Barmar, Jul 16 '21 at 20:57
mediocrity's answer is the first one marked as a correct. Though that's irrelevant, the point is I borrowed the code from him and changed a little to suit my needs. — The August Georgian, Jul 16 '21 at 20:58
His code gives me the following output: `Input something: ` after five seconds its `Input something: Too Slow` and on the next line program still expects an input from user, it doesn't terminate — The August Georgian, Jul 16 '21 at 21:00
If you put `print("Too slow")` before `sys.exit()` in your code above, do you get that message? But it still doesn't exit the script? — Barmar, Jul 16 '21 at 21:02
See https://stackoverflow.com/questions/1489669/how-to-exit-the-entire-application-from-a-python-thread — Barmar, Jul 16 '21 at 21:07
And https://stackoverflow.com/questions/905189/why-does-sys-exit-not-exit-when-called-inside-a-thread-in-python — Barmar, Jul 16 '21 at 21:07
`os._exit(1)` worked from [Mark Rushakoff's answer](https://stackoverflow.com/a/1489838/16462417). Thanks tons! — The August Georgian, Jul 16 '21 at 21:17

score 0 · Answer 1 · answered Jul 22 '21 at 16:41

you should try this code its working on vscode

import sys
import time
from threading import Thread

x = None

def check():
  global x
  time.sleep(5)
  if x:
    print("Input has been given!")
    return
  else:
    print("input has not been given for last 5 sec") 
    sys.exit()
if __name__=='__main__':
  t1=Thread(target=check)
  t1.start()

  x = input("Input something: ")
  t1.join()

Terminate Python program if input isn't specified in due timeframe

1 Answers1