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    if countinue == "No" or "no" :
  print ("Your journey is then from ",inp,"to",ins)
  if ins in mix1 and inp in mix1:
    print("Your fare is : £4.00")
  elif ins in mix2 and inp in mix2:
    print("Your fare is : £3.00 ")
  elif ins in mix3 and inp in mix3:
    print("Your fare is : £2.00")
  elif ins in mix1 and inp in mix2 or ins in mix2 and inp in mix1:
    print("Your fare is : £3.50 ")
  elif ins in mix1 and inp in mix3 or ins in mix3 and inp in mix1 :
    print("Your fare is : £3.00") 
  elif ins in mix2 and inp in mix3 or ins in mix3 and inp in mix2:
    print("Your fare is : £2.35")
PM 77-1
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zain surty
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    `if countinue == "No" or "no" :` does not work the way you expect it. It will be **always** `true`. – PM 77-1 Jul 23 '21 at 21:18

1 Answers1

0

You need to declare the full question each time.

if countinue == "No" or continue == "no"

If you're doing this just because of the capital letter, you can use the lower method instead.

if countinue.lower() == "no"

This changes the variable data to lowercase before analysing it.

Luke
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