Function to test if String length is odd or even

Question

I am writing a function to test if a string length is odd or even, but running into some issue when I try to test the result. I get back the result odd, and None. I need it run for the test result but it's testing my function value. What am I missing here? Thanks.

Below is the function:

    def strEorO(inputVal):

       if len(inputVal) % 2 == 0:
          print('even')
       else:
          print('odd')

Here is where i am testing the function:

   result = strEorO('airplane')
   print(result)

That is because `print` is not same as `return`. Instead of `print` within the function, use `return`. i.e. `return 'even' if len(inputVal) % 2 == 0 else 'odd'` — shahkalpesh, Jul 24 '21 at 19:20
That's because you don't return anything from the function. Change your *print*s to *return*s (e.g. `return "even"`). — CristiFati, Jul 24 '21 at 19:21
Got it. So i need to change the print even or print odd to return even or return odd. — Joe 5, Jul 24 '21 at 19:25

score 2 · Accepted Answer · answered Jul 24 '21 at 19:27

As was discussed in the comments, your function isn't returning anything, so printing the result will print None. Use either of these two methods instead:

Return the Output, then Print:

def evenOrOdd(string):
  if len(string) % 2 == 0:
     return "Even"
  else:
     return "Odd"

result = evenOrOdd('hello')
print(result)

Return nothing, print within function:

def evenOrOdd(string):
   if len(string) % 2 == 0:
      print('Even')
   else:
      print('Odd')

evenOrOdd('hello')

Function to test if String length is odd or even

1 Answers1