I have this dataset:
1 "MX000017004195504TMAX  310  I  310  I  310  I  320  I  330  I  320  I  320  I  330  I  330  I  330  I  330~
 2 "MX000017004195504TMIN  150  I  150  I  160  I  150  I  160  I  160  I  160  I  160  I  160  I  170  I  170~
 3 "MX000017004195504PRCP    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0~
 4 "MX000017004195505TMAX  310  I  310  I  310  I  300  I  300  I  300  I  310  I  310  I  310  I  300  I  300~
 5 "MX000017004195505TMIN  200  I  160  I  160  I  150  I  150  I  150  I  160  I  160  I  170  I  170  I  170~
 6 "MX000017004195505PRCP    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0  I    0~
 7 "MX000017004195506TMAX  300  I  290  I  280  I  270  I  280  I  260  I  230  I  270  I  280  I  280  I  270~
 8 "MX000017004195506TMIN  160  I  160  I  150  I  140  I  160  I  150  I  150  I  150  I  160  I  150  I  160~
 9 "MX000017004195506PRCP  103  I  435  I  422  I    0  I  243  I   17  I    0  I    0  I    0  I   27  I    0~
10 "MX000017004195507TMAX  270  I  270  I  260  I  260  I  240  I  240  I  190  I  210  I  250  I  250  I  260~
# ... with 1,704 more rows
I need to make every string or digit after the "I" letter in a column.
I tried:
# To separate age to 2 columns 
weather <- weather %>%
     separate(weather$V1, into= c("Date", "values"), sep = "I")
But it did not work.
 
    