Why python returns None not True?

Question

I expected my method call print(isFour(16)) returns "True", but it actually returned "None". What's wrong?

def isFour(int):
    if int == 4: return True
    if int > 0:
       isPositive(int/2)
        
print(isFour(16)) # expected output is True, but got None

Because it *does not* `return` anything in the second `if` branch, and/or `isPositive` may not `return` anything… — deceze, Sep 16 '21 at 08:11
Replace `isPositive(int/2)` with `isFour(int/2)` s.t. you actually have a recursive function. — Timus, Sep 16 '21 at 08:25

score 0 · Answer 1 · answered Sep 16 '21 at 08:18

0

It return None since int is not 4.

If you want it to return true if int is in the 4 times table you should write:

if int % 4 == 0: return True

answered Sep 16 '21 at 08:18

andr4229

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Or just `return int % 4 === 0`, so it returns `True` or `False` always… – deceze Sep 16 '21 at 08:21
Please don't encourage naming a variable `int`!! – Stef Sep 16 '21 at 09:49

Why python returns None not True?

1 Answers1