Get the two foreach array the top one's index?

Question

is that a way to get the top parten foreach's index? by two using foreach array?

ForEach(total, id: \.id){ item in
    ForEach(nameber, id: \.id){ item in
        (get the total;s index)
    }
}

Could you add some sample data and expected output to make it clearer what you want? — Joakim Danielson, Sep 18 '21 at 07:11
Does this answer your question? [How to iterate a loop with index and element in Swift](https://stackoverflow.com/questions/24028421/how-to-iterate-a-loop-with-index-and-element-in-swift) — Commander Tvis, Sep 18 '21 at 12:17

George · Answer 1 · 2021-09-18T03:31:23.660

You need to give the content's input different variable names.

You have both of them as item, so if you have different names, you can access the outside variable - not just the inside one.

Example:

struct ContentView: View {
    var body: some View {
        ForEach(0 ..< 5) { i in
            ForEach(0 ..< 5) { j in
                Text("(i: \(i), j: \(j))")
            }
        }
    }
}

Result:

Variables renamed to match your example (using implicit (id: \.id, assuming they conform to Identifiable):

struct ContentView: View {
    var body: some View {
        ForEach(total) { totalItem in
            ForEach(nameber) { nameberItem in
                Text("(totalItem: \(totalItem), nameberItem: \(nameberItem))")
            }
        }
    }
}

score 0 · Accepted Answer · answered Sep 18 '21 at 03:25

very criptic question. Try this, to get the index and the item of the outer ForEach:

    ForEach(Array(total.enumerated()), id: \.1) { index, item in
        ForEach(member, id: \.id) { item2 in
            Text(String(index) + " \(item)" + " \(item2)")
        }
    }

Get the two foreach array the top one's index?

2 Answers2