Python output string with transition characters and double quotes

Question

I want to output the following string n times.

" add x0,x0,x0      # placefold  \n\t" \

When I use

placeholder=r'" add x0,x0,x0      # placefold  \n\t" \' 
print(placeholder)

EOL while scanning string literal error occurred. I clearly added r in front of the string, why does this error still occur.

When i use

placeholder=r'" add x0,x0,x0      # placefold  \n\t" \ ' 
print(placeholder)

(I added a space before the'.)

There is no error after running. But I don’t want an extra space at the end.

what should I do? What I want to achieve is:

placeholder=(r'" add x0,x0,x0      # placefold  \n\t" \' +"\n")*repeat_number
print(placeholder)

Thanks!

the \ at the end of string is unnessesary, thats the cause of the error — Ghost Ops, Sep 29 '21 at 13:12

score 1 · Answer 1 · answered Sep 29 '21 at 13:23

1

You can use string concatentation without the + operator, I suggest using this code:

placeholder=r'" add x0,x0,x0      # placefold  \n\t" ' '\' 
print(placeholder)

Notice, that "ab" is equal to "a" "b" (this works too in C).

answered Sep 29 '21 at 13:23

FaranAiki

453
3
12

RobBlanchard · Answer 2 · 2021-09-29T13:31:59.690

1

If you want placeholder to end with a backslash, consider escaping it:

placeholder = r'" add x0,x0,x0      # placefold  \n\t" \\'
print(placeholder)

Results in: " add x0,x0,x0 # placefold \n\t" \\. It looks like there are two backslashes, but there is actually only one. The console prints \\ to notify a single backslash in this case. Proof:

>>> placeholder[-1]
'\\'

edited Sep 29 '21 at 13:31

answered Sep 29 '21 at 13:24

RobBlanchard

855
3
17

1

But it ends up with double '\', which is not what the OP wants. – FaranAiki Sep 29 '21 at 13:25
Incorrect. Should only end with 1 slash. – Niel Godfrey Pablo Ponciano Sep 29 '21 at 13:26
Edited my answer to prove there is actually only one backslash. – RobBlanchard Sep 29 '21 at 13:32
"The console prints \\ to notify a single backslash in this case. Proof," of course, because **that is the last character**, which is `\\`. Try to print the result, you got two backslashes. – FaranAiki Sep 29 '21 at 13:43
Or check with `"abbb"`, there are three `b`, but if you print the `[-1]`, you will get "b". – FaranAiki Sep 29 '21 at 13:47

Python output string with transition characters and double quotes

2 Answers2