I'm kinda new to assembly and I want to know how to get a char ASCII code and print out that ASCII code. I'm using MASM (Dosbox).
MOV AX, 'A' ; -> I want to print out the ASCII code of 'A'
Thanks for the answers!
Asked
Active
Viewed 1,560 times
0
Sep Roland
- 33,889
- 7
- 43
- 76
daniel19
- 67
- 8
-
You mean you want to print `65`? Just print `AX` as a number. Divide by 10, print the two digits. – Jester Oct 18 '21 at 19:42
-
@Jester like this?: MOV AX, 'A' MOV BX, 10 DIV BL MOV AH, 2 INT 21h – daniel19 Oct 18 '21 at 19:50
-
You will need to handle both digits and have to convert back to text (add `'0'`). – Jester Oct 18 '21 at 19:52
-
After DIV: ADD AH, 48 ADD AL, 48? – daniel19 Oct 18 '21 at 19:57
-
Yes but you will have to print them separately. – Jester Oct 18 '21 at 19:59
-
I got this output: ## – daniel19 Oct 18 '21 at 20:04
-
1Read about how to solve this in https://stackoverflow.com/questions/45904075/displaying-numbers-with-dos. – Sep Roland Oct 18 '21 at 20:10
1 Answers
2
From comments
MOV AX, 'A'MOV BX, 10DIV BLMOV AH, 2INT 21h
This byte-sized division will leave a quotient in AL and a remainder in AH.
But the DOS.PrintCharacter function 02h expects its input in the DL register.
After DIV:
ADD AH, 48ADD AL, 48
Fine to convert, but you can do it in one go with ADD AX, 3030h
I got this output: ##
Try next code:
mov ax, 'A'
mov bl, 10
div bl
add ax, 3030h
mov dx, ax ; Moving tens "6" to DL for printing and preserving the units in DH
mov ah, 02h ; DOS.PrintCharacter
int 21h
mov dl, dh ; units "5"
mov ah, 02h ; DOS.PrintCharacter
int 21h
Displaying numbers with DOS has a detailed explanation about how to deal with even bigger numbers.
Sep Roland
- 33,889
- 7
- 43
- 76
-
1First `mov ah, 02h` clobbers `ah` before loading it into `dl`. Better: `mov dx, ax` and `mov dl, dh` – ecm Oct 18 '21 at 21:28
-
I tried the code, but got this output: ##65. The question is why am i getting this: ## – daniel19 Oct 19 '21 at 07:20
-
@daniel19 Those ## must come from *something earlier on* in your program. The code snippet that I posted can not output by itself those redundant characters. Why don't you edit the question and include the whole program source? – Sep Roland Oct 19 '21 at 18:42