why '@' and '.' in 'heykidhellogmail.com' returns True?

Question

hello i tried to make a email parser but it behaves weirdly can someone tell me why

def parser(wrds):
    s = set()
    for wrd in wrds:
        splited_wrd = wrd.split(' ')
        for i in range(len(splited_wrd)):
            wrds_indexed = splited_wrd[i]
            if ('@' and '.' in wrds_indexed) and (len(wrds_indexed) > 13):
                s.add(wrds_indexed)
    yield from s


x = 'heykidhello@gmail.com', 'heykidgmail.com', 'heykidhello@gmailcom','h@gmail.com'
print(list(parser(x)))

output:

['heykidgmail.com', 'heykidhello@gmail.com']                                                                                                                                            
>>>

can someone tell me why does heykidgmail.com is in the list when it clearly doesnt have '@'

>>> '@' and '.' in 'heykidgmail.com'                                                                                                                                                    
True

when i ran it in console why does it say True when @ is not in the word ?

Use `'@' in 'heykidgmail.com' and '.' in 'heykidgmail.com'` – I_Al-thamary Oct 30 '21 at 18:00 — I_Al-thamary, Oct 30 '21 at 18:00

score 3 · Accepted Answer · answered Oct 30 '21 at 17:59

3

'@' and '.' in 'heykidgmail.com'

does not do what you think it does.

It is interpreted as

bool('@')  and  bool('.' in 'heykidgmail.com')

Or

True  and  bool('.' in 'heykidgmail.com')

Thus

bool('.' in 'heykidgmail.com')

You need to test both independently:

s = 'heykidgmail.com'
'@' in s and '.' in s

answered Oct 30 '21 at 17:59

Jonathon Reinhart

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now i understand thank you for your help – Jishnu Oct 30 '21 at 18:07

why '@' and '.' in 'heykidhellogmail.com' returns True?

1 Answers1