Deserialize json where an attribute has the same name as a built in datatype, in C#

Question

I faced a problem that I could not find any solution to by google...

   JavaScriptSerializer js = new JavaScriptSerializer();
   MyClass myObject = js.Deserialize<MyClass>(jsonstring);

What about if an attribute in the json data is called "short"? I cannot make a class like this:

public class MyClass
{
   public int A;        
   public int B;       
   public int short;
}

So how can I get the jsonstring into an object in an easy way? Very thankful for all help I can get.

Does this answer your question? [JavaScriptSerializer - custom property name](https://stackoverflow.com/questions/32487483/javascriptserializer-custom-property-name) and specifically [that](https://stackoverflow.com/a/32488106/1797425) answer... — Trevor, Nov 04 '21 at 19:35

score 1 · Answer 1 · answered Nov 04 '21 at 19:25

1

You can use @ in

public class MyClass
{
   public int A;        
   public int B;       
   public int @short;
}

answered Nov 04 '21 at 19:25

Balastrong

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Could you clarify in your answer what `@` means in this context? – Trevor Nov 04 '21 at 19:36

score 1 · Answer 2 · edited Nov 05 '21 at 00:06

short is a keyword (documentation; you will need to call the variable something else. Short would work just fine since keywords are case sensitive, and all keywords are lowercase.

In @Balastrong's answer:

public class MyClass
{
   public int A;        
   public int B;       
   public int @short;
}

The @ symbol is being used as a "verbatim identifier" (documentation; see number 1). This allows the interpreter to understand @short as the identifier short instead of the keyword short.

Hope this cleared some things up.

Deserialize json where an attribute has the same name as a built in datatype, in C#

2 Answers2