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Why it's correct:

Long l = new Long(10);

but it's not correct:

Long l2 = 10;

I understand that int is substituted here, but why is new Long(10) correct?

ernest_k
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EuginK
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    `10` is an `int` (`10L` would be a `long`). And an `int` doesn't get boxed into a `Long`. Boxing `10` to `Integer` doesn't make it a `Long`, because an `Integer` is **not** a `Long`. – ernest_k Nov 05 '21 at 10:19
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    The constructor of `Long` takes a `long`, which the `int` can be converted to. In the second example, a `int` or the autoboxed `Integer` can not be assigned to a `Long` though. You can use a `long` literal to make it work, use `Long l2 = 10L;`. – f1sh Nov 05 '21 at 10:25

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