How to remove from an array the elements that are present in a second array

Question

I'm trying to clean an array (secondArray) by removing those elements that are also included in another array (secondRegex). This is one of my latest attempts, but it doesn't work :'( The result I get is: 0[]. Why????????

const secondRegex = ['i', 'a', 'about', 'am', 'an', 'are', 'as', 'at', 'be', 'by', 'for', 'from', 'how', 'in', 'is', 'it', 'of', 'on', 'or', 'that', 'the', 'this', 'to', 'was', 'what', 'when', 'where', 'who', 'will', 'with'];
const secondArray = ['i', 'am','a', 'very', 'happy', 'child'];

let myList = []
for (let i = 0; i < secondArray; i++){
    let is_the_same = 0;
    for (let j = 0; j < secondRegex; j++){
        if(secondArray[i] == secondRegex[j]){
            is_the_same = 1;
            break;

        }
    }if (!is_the_same){
        myList.push(secondArray[i]);
    }
}
console.log(myList);

I have also tried this with no success:

for (let i = 0; i < secondArray.length; i++){
    let value = secondArray[i];
    let coincidence = secondArray.some(value => secondRegex.includes(value));
    }if (coincidence = true){
        continue;
    }
    else{
    myList.push(secondArray[i]);
}