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I am new to c coding, my program is running well when use int data type, but when I use char it starts skipping line.

#include <stdio.h>

int main() {
    int i;
    char k[10];
    for (i = 0; i < 10; i++) {
        printf("enter your character for line %d: \n", i);
        scanf("%c", &k[i]);
    }
    for (i = 0; i < 10; i++) {
        printf("your character for line %d are %c \n", i, k[i]);
    }

    return 0;
}
chqrlie
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Krishna Agrawal
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1 Answers1

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Well, when you press Enter you are writting 'new line' character to program's input.
And because it's character, %c is reading it.

Specifier %c doesn't consume spaces like other specifiers, so you have to explicitly tell scanf to skip whitespaces, by adding space before %c, so you will have " %c" as format.

More details might be here:
https://stackoverflow.com/a/5240807/2416941

EDIT: Be aware that this way you can't read space or tabs from user's input.

Tundy
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