Why is this parse error here Parse error: syntax error, unexpected identifier "edit", expecting "," or ";"?

Question

  <td>{$row['date']}</td>
          <td><a href="edit.php?applicationid=<?php echo $data['applicationid']; ?>">Edit</a></td>

        </tr>";

In 2nd line I am getting this error: Parse error: syntax error, unexpected identifier "edit", expecting "," or ";"

The double quote in `href="edit` is ending your string. Either change that to a single quote or escape it with backslash. — Barmar, Dec 21 '21 at 20:33
It is not working with single quote Parse error: syntax error, unexpected string content "", expecting "-" or identifier or variable or number in C:\xampp\htdocs\users\admin.php on line 98 — Hamna, Dec 21 '21 at 20:46

score 1 · Accepted Answer · answered Dec 21 '21 at 20:55

This appears to be part of a string literal, and you're ending the listeral with the " in href=". You need to escape that or use single quotes.

Also, you don't use <?php echo $variable ?> to embed a variable in a string, you use {$variable}, like yo udid with $row['date']

echo "<td>{$row['date']}</td>
          <td><a href='edit.php?applicationid={$data['applicationid']}'>Edit</a></td>

        </tr>";

1 Answers1